How do you find min and max in divide and conquer?

How do you find min and max in divide and conquer?

1. import sys. # Divide and conquer solution to find the minimum and maximum number in a list.
2. def findMinAndMax(nums, left, right, min=sys. maxsize, max=-sys.
3. if left == right: # common comparison.
4. min = nums[right]
5. max = nums[left]
6. # if the list contains only two elements.
7. if nums[left] < nums[right]: # comparison 1.

What are the number of comparisons needed for Max Min algorithm if t/n represents the number?

Method 1: if we apply the general approach to the array of size n, the number of comparisons required are 2n-2.

What are the three sequential steps of Divide and Conquer algorithm?

You should think of a divide-and-conquer algorithm as having three parts:

• Divide the problem into a number of subproblems that are smaller instances of the same problem.
• Conquer the subproblems by solving them recursively.
• Combine the solutions to the subproblems into the solution for the original problem.

How do you find max and min in C?

Logic to find maximum and minimum element in array Input size and element in array, store it in some variable say size and arr . Declare two variables max and min to store maximum and minimum. Assume first array element as maximum and minimum both, say max = arr[0] and min = arr[0] .

What is the maximum and minimum problem?

The process of finding maximum or minimum values is called optimisation. We are trying to do things like maximise the profit in a company, or minimise the costs, or find the least amount of material to make a particular object. These are very important in the world of industry.

What is the max min problem?

Max-Min problem is to find a maximum and minimum element from the given array. We can effectively solve it using divide and conquer approach. In the traditional approach, the maximum and minimum element can be found by comparing each element and updating Max and Min values as and when required.

What will be minimum number of comparisons required to find the minimum and the maximum of 100 numbers?

The minimum number of comparisons required to find the minimum and the maximum of 100 numbers is ______________. Therefore, we need 3 comparisons for each 2 elements, so total number of required comparisons will be (3n)/2 – 2, because we do not need to update min or max in the very first step.

What is the time complexity of the MIN MAX problem using divide and conquer?

It’s true that using divide and conquer the time complexity for finding min and max is O(n). But using divide and conquer the number of comparisons can be reduced to a great extent which indeed reduces time if the data is huge. So divide and conquer approach does 3/2n -2 comparisons if n is a power of 2.

How do you find the max and min of an array?

The function getresult( int arr[],int n) is to find the maximum and minimum element present in the array in minimum no. of comparisons. If there is only one element then we will initialize the variables max and min with arr[0] . For more than one element, we will initialize max with arr[1] and min with arr[0].

What is divide and conquer algorithm?

Like Greedy and Dynamic Programming, Divide and Conquer is an algorithmic paradigm. A typical Divide and Conquer algorithm solves a problem using following three steps. 1. Divide: Break the given problem into subproblems of same type. 2. Conquer: Recursively solve these subproblems.

What are some simple problems that can be solved by divide and conquer?

Let us consider a simple problem that can be solved by divide and conquer technique. The Max-Min Problem in algorithm analysis is finding the maximum and minimum value in an array. To find the maximum and minimum numbers in a given array numbers [] of size n, the following algorithm can be used.

What are the three parts of divide and conquer?

Divide And Conquer This technique can be divided into the following three parts: 1 Divide: This involves dividing the problem into some sub problem. 2 Conquer: Sub problem by calling recursively until sub problem solved. 3 Combine: The Sub problem Solved so that we will get find problem solution.

How to find the maximum and minimum numbers of comparison?

To find the maximum and minimum numbers, the following straightforward algorithm can be used. The number of comparison in Naive method is 2n – 2. The number of comparisons can be reduced using the divide and conquer approach.